Solve 7-6a+6h+4(a+h)^2

$$7 - 6 a + 6 h + 4 ( a + h ) ^ { 2 }$$

Evaluate

$$4\left(a+h\right)^{2}+6h-6a+7$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+h\right)^{2}.

$$7-6a+6h+4\left(a^{2}+2ah+h^{2}\right)$$

Use the distributive property to multiply 4 by a^{2}+2ah+h^{2}.

$$7-6a+6h+4a^{2}+8ah+4h^{2}$$

Expand

$$4a^{2}+8ah-6a+4h^{2}+6h+7$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(a+h\right)^{2}.

$$7-6a+6h+4\left(a^{2}+2ah+h^{2}\right)$$

Use the distributive property to multiply 4 by a^{2}+2ah+h^{2}.

$$7-6a+6h+4a^{2}+8ah+4h^{2}$$