Solve 7-35/6+11/4=

$$7 - 3 \frac { 5 } { 6 } + 1 \frac { 1 } { 4 } =$$

Evaluate

$$\frac{53}{12}\approx 4.416666667$$

Solution Steps

Multiply 3 and 6 to get 18.

$$7-\frac{18+5}{6}+\frac{1\times 4+1}{4}$$

Add 18 and 5 to get 23.

$$7-\frac{23}{6}+\frac{1\times 4+1}{4}$$

Convert 7 to fraction \frac{42}{6}.

$$\frac{42}{6}-\frac{23}{6}+\frac{1\times 4+1}{4}$$

Since \frac{42}{6} and \frac{23}{6} have the same denominator, subtract them by subtracting their numerators.

$$\frac{42-23}{6}+\frac{1\times 4+1}{4}$$

Subtract 23 from 42 to get 19.

$$\frac{19}{6}+\frac{1\times 4+1}{4}$$

Multiply 1 and 4 to get 4.

$$\frac{19}{6}+\frac{4+1}{4}$$

Add 4 and 1 to get 5.

$$\frac{19}{6}+\frac{5}{4}$$

Least common multiple of 6 and 4 is 12. Convert \frac{19}{6} and \frac{5}{4} to fractions with denominator 12.

$$\frac{38}{12}+\frac{15}{12}$$

Since \frac{38}{12} and \frac{15}{12} have the same denominator, add them by adding their numerators.

$$\frac{38+15}{12}$$

Add 38 and 15 to get 53.

$$\frac{53}{12}$$

Factor

$$\frac{53}{2 ^ {2} \cdot 3} = 4\frac{5}{12} = 4.416666666666667$$