Solve 7-[8x-3(x+3)]=5x-(4-2x)

$$7 - [ 8 x - 3 ( x + 3 ) ] = 5 x - ( 4 - 2 x )$$

Solve for x

$$x = \frac{5}{3} = 1\frac{2}{3} \approx 1.666666667$$

Steps for Solving Linear Equation

Use the distributive property to multiply -3 by x+3.

$$7-\left(8x-3x-9\right)=5x-\left(4-2x\right)$$

Combine 8x and -3x to get 5x.

$$7-\left(5x-9\right)=5x-\left(4-2x\right)$$

To find the opposite of 5x-9, find the opposite of each term.

$$7-5x-\left(-9\right)=5x-\left(4-2x\right)$$

The opposite of -9 is 9.

$$7-5x+9=5x-\left(4-2x\right)$$

Add 7 and 9 to get 16.

$$16-5x=5x-\left(4-2x\right)$$

To find the opposite of 4-2x, find the opposite of each term.

$$16-5x=5x-4-\left(-2x\right)$$

The opposite of -2x is 2x.

$$16-5x=5x-4+2x$$

Combine 5x and 2x to get 7x.

$$16-5x=7x-4$$

Subtract 7x from both sides.

$$16-5x-7x=-4$$

Combine -5x and -7x to get -12x.

$$16-12x=-4$$

Subtract 16 from both sides.

$$-12x=-4-16$$

Subtract 16 from -4 to get -20.

$$-12x=-20$$

Divide both sides by -12.

$$x=\frac{-20}{-12}$$

Reduce the fraction \frac{-20}{-12} to lowest terms by extracting and canceling out -4.

$$x=\frac{5}{3}$$