Solve 7(r-3)geq-13

$$7 ( r - 3 ) \geq - 13$$

Solve for r

$$r\geq \frac{8}{7}$$

Solution Steps

Divide both sides by 7. Since 7 is positive, the inequality direction remains the same.

$$r-3\geq -\frac{13}{7}$$

Add 3 to both sides.

$$r\geq -\frac{13}{7}+3$$

Convert 3 to fraction \frac{21}{7}.

$$r\geq -\frac{13}{7}+\frac{21}{7}$$

Since -\frac{13}{7} and \frac{21}{7} have the same denominator, add them by adding their numerators.

$$r\geq \frac{-13+21}{7}$$

Add -13 and 21 to get 8.

$$r\geq \frac{8}{7}$$