Solve 7(3b+4)-4(b-5)-2(2b+11)=0

$$7 ( 3 b + 4 ) - 4 ( b - 5 ) - 2 ( 2 b + 11 ) = 0$$

Solve for b

$$b=-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply 7 by 3b+4.

$$21b+28-4\left(b-5\right)-2\left(2b+11\right)=0$$

Use the distributive property to multiply -4 by b-5.

$$21b+28-4b+20-2\left(2b+11\right)=0$$

Combine 21b and -4b to get 17b.

$$17b+28+20-2\left(2b+11\right)=0$$

Add 28 and 20 to get 48.

$$17b+48-2\left(2b+11\right)=0$$

Use the distributive property to multiply -2 by 2b+11.

$$17b+48-4b-22=0$$

Combine 17b and -4b to get 13b.

$$13b+48-22=0$$

Subtract 22 from 48 to get 26.

$$13b+26=0$$

Subtract 26 from both sides. Anything subtracted from zero gives its negation.

$$13b=-26$$

Divide both sides by 13.

$$b=\frac{-26}{13}$$

Divide -26 by 13 to get -2.

$$b=-2$$