Solve 7(31/7-7*1/4)=

$$7 ( 3 \frac { 1 } { 7 } - 7 \cdot \frac { 1 } { 4 } ) =$$

Evaluate

$$\frac{39}{4}=9.75$$

Solution Steps

Multiply 3 and 7 to get 21.

$$7\left(\frac{21+1}{7}-7\times \frac{1}{4}\right)$$

Add 21 and 1 to get 22.

$$7\left(\frac{22}{7}-7\times \frac{1}{4}\right)$$

Multiply 7 and \frac{1}{4} to get \frac{7}{4}.

$$7\left(\frac{22}{7}-\frac{7}{4}\right)$$

Least common multiple of 7 and 4 is 28. Convert \frac{22}{7} and \frac{7}{4} to fractions with denominator 28.

$$7\left(\frac{88}{28}-\frac{49}{28}\right)$$

Since \frac{88}{28} and \frac{49}{28} have the same denominator, subtract them by subtracting their numerators.

$$7\times \frac{88-49}{28}$$

Subtract 49 from 88 to get 39.

$$7\times \frac{39}{28}$$

Express 7\times \frac{39}{28} as a single fraction.

$$\frac{7\times 39}{28}$$

Multiply 7 and 39 to get 273.

$$\frac{273}{28}$$

Reduce the fraction \frac{273}{28} to lowest terms by extracting and canceling out 7.

$$\frac{39}{4}$$

Factor

$$\frac{3 \cdot 13}{2 ^ {2}} = 9\frac{3}{4} = 9.75$$