Factor
7\left(x-2y\right)\left(x^{2}+2xy+4y^{2}\right)
Evaluate
7\left(x^{3}-8y^{3}\right)
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7\left(x^{3}-8y^{3}\right)
Factor out 7.
\left(x-2y\right)\left(x^{2}+2xy+4y^{2}\right)
Consider x^{3}-8y^{3}. Rewrite x^{3}-8y^{3} as x^{3}-\left(2y\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).
7\left(x-2y\right)\left(x^{2}+2xy+4y^{2}\right)
Rewrite the complete factored expression.
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