Solve 7x^2-4left(x^2+x+2right)=3x^2+4x+8

$$7 { x }^{ 2 } -4 \left( { x }^{ 2 } +x+2 \right) = 3 { x }^{ 2 } +4x+8$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Use the distributive property to multiply -4 by x^{2}+x+2.

$$7x^{2}-4x^{2}-4x-8=3x^{2}+4x+8$$

Combine 7x^{2} and -4x^{2} to get 3x^{2}.

$$3x^{2}-4x-8=3x^{2}+4x+8$$

Subtract 3x^{2} from both sides.

$$3x^{2}-4x-8-3x^{2}=4x+8$$

Combine 3x^{2} and -3x^{2} to get 0.

$$-4x-8=4x+8$$

Subtract 4x from both sides.

$$-4x-8-4x=8$$

Combine -4x and -4x to get -8x.

$$-8x-8=8$$

Add 8 to both sides.

$$-8x=8+8$$

Add 8 and 8 to get 16.

$$-8x=16$$

Divide both sides by -8.

$$x=\frac{16}{-8}$$

Divide 16 by -8 to get -2.

$$x=-2$$