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7x^{2}-94=0
Subtract 137 from 43 to get -94.
7x^{2}=94
Add 94 to both sides. Anything plus zero gives itself.
x^{2}=\frac{94}{7}
Divide both sides by 7.
x=\frac{\sqrt{658}}{7} x=-\frac{\sqrt{658}}{7}
Take the square root of both sides of the equation.
7x^{2}-94=0
Subtract 137 from 43 to get -94.
x=\frac{0±\sqrt{0^{2}-4\times 7\left(-94\right)}}{2\times 7}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 7 for a, 0 for b, and -94 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 7\left(-94\right)}}{2\times 7}
Square 0.
x=\frac{0±\sqrt{-28\left(-94\right)}}{2\times 7}
Multiply -4 times 7.
x=\frac{0±\sqrt{2632}}{2\times 7}
Multiply -28 times -94.
x=\frac{0±2\sqrt{658}}{2\times 7}
Take the square root of 2632.
x=\frac{0±2\sqrt{658}}{14}
Multiply 2 times 7.
x=\frac{\sqrt{658}}{7}
Now solve the equation x=\frac{0±2\sqrt{658}}{14} when ± is plus.
x=-\frac{\sqrt{658}}{7}
Now solve the equation x=\frac{0±2\sqrt{658}}{14} when ± is minus.
x=\frac{\sqrt{658}}{7} x=-\frac{\sqrt{658}}{7}
The equation is now solved.