Solve 7*4-x^{3}-5x^2-6x+1-2x^4+3x^3-3x^2-x+3=

$$7 \times 4 - x ^ { 3 } - 5 x ^ { 2 } - 6 x + 1 - 2 x ^ { 4 } + 3 x ^ { 3 } - 3 x ^ { 2 } - x + 3 =$$

Evaluate

$$32-7x-8x^{2}+2x^{3}-2x^{4}$$

Solution Steps

Multiply 7 and 4 to get 28.

$$28-x^{3}-5x^{2}-6x+1-2x^{4}+3x^{3}-3x^{2}-x+3$$

Add 28 and 1 to get 29.

$$29-x^{3}-5x^{2}-6x-2x^{4}+3x^{3}-3x^{2}-x+3$$

Combine -x^{3} and 3x^{3} to get 2x^{3}.

$$29+2x^{3}-5x^{2}-6x-2x^{4}-3x^{2}-x+3$$

Combine -5x^{2} and -3x^{2} to get -8x^{2}.

$$29+2x^{3}-8x^{2}-6x-2x^{4}-x+3$$

Combine -6x and -x to get -7x.

$$29+2x^{3}-8x^{2}-7x-2x^{4}+3$$

Add 29 and 3 to get 32.

$$32+2x^{3}-8x^{2}-7x-2x^{4}$$

Differentiate w.r.t. x

$$-8x^{3}+6x^{2}-16x-7$$