Solve 7*2^8+2^6+3*2^3-2^3

$$7 \times 2 ^ { 8 } + 2 ^ { 6 } + 3 \times 2 ^ { 3 } - 2 ^ { 3 }$$

Evaluate

$$1872$$

Solution Steps

Calculate 2 to the power of 8 and get 256.

$$7\times 256+2^{6}+3\times 2^{3}-2^{3}$$

Multiply 7 and 256 to get 1792.

$$1792+2^{6}+3\times 2^{3}-2^{3}$$

Calculate 2 to the power of 6 and get 64.

$$1792+64+3\times 2^{3}-2^{3}$$

Add 1792 and 64 to get 1856.

$$1856+3\times 2^{3}-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$1856+3\times 8-2^{3}$$

Multiply 3 and 8 to get 24.

$$1856+24-2^{3}$$

Add 1856 and 24 to get 1880.

$$1880-2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$1880-8$$

Subtract 8 from 1880 to get 1872.

$$1872$$

Factor

$$2^{4}\times 3^{2}\times 13$$