Solve 7*6-40div6+6^2(8+18)

$$7 \times 6-40 \div 6+ { 6 }^{ 2 } (8+18)$$

Evaluate

$$\frac{2914}{3}\approx 971.333333333$$

Solution Steps

Multiply 7 and 6 to get 42.

$$42-\frac{40}{6}+6^{2}\left(8+18\right)$$

Reduce the fraction \frac{40}{6} to lowest terms by extracting and canceling out 2.

$$42-\frac{20}{3}+6^{2}\left(8+18\right)$$

Convert 42 to fraction \frac{126}{3}.

$$\frac{126}{3}-\frac{20}{3}+6^{2}\left(8+18\right)$$

Since \frac{126}{3} and \frac{20}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{126-20}{3}+6^{2}\left(8+18\right)$$

Subtract 20 from 126 to get 106.

$$\frac{106}{3}+6^{2}\left(8+18\right)$$

Calculate 6 to the power of 2 and get 36.

$$\frac{106}{3}+36\left(8+18\right)$$

Add 8 and 18 to get 26.

$$\frac{106}{3}+36\times 26$$

Multiply 36 and 26 to get 936.

$$\frac{106}{3}+936$$

Convert 936 to fraction \frac{2808}{3}.

$$\frac{106}{3}+\frac{2808}{3}$$

Since \frac{106}{3} and \frac{2808}{3} have the same denominator, add them by adding their numerators.

$$\frac{106+2808}{3}$$

Add 106 and 2808 to get 2914.

$$\frac{2914}{3}$$

Factor

$$\frac{2 \cdot 31 \cdot 47}{3} = 971\frac{1}{3} = 971.3333333333334$$