Solve 7*{left(1/7right)}^2-8*1/7

$$7 \times { \left( \frac{ 1 }{ 7 } \right) }^{ 2 } -8 \times \frac{ 1 }{ 7 }$$

Evaluate

$$-1$$

Solution Steps

Calculate \frac{1}{7} to the power of 2 and get \frac{1}{49}.

$$7\times \frac{1}{49}-8\times \frac{1}{7}$$

Multiply 7 and \frac{1}{49} to get \frac{7}{49}.

$$\frac{7}{49}-8\times \frac{1}{7}$$

Reduce the fraction \frac{7}{49} to lowest terms by extracting and canceling out 7.

$$\frac{1}{7}-8\times \frac{1}{7}$$

Multiply 8 and \frac{1}{7} to get \frac{8}{7}.

$$\frac{1}{7}-\frac{8}{7}$$

Since \frac{1}{7} and \frac{8}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{1-8}{7}$$

Subtract 8 from 1 to get -7.

$$\frac{-7}{7}$$

Divide -7 by 7 to get -1.

$$-1$$

Factor

$$-1$$