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126\sqrt{2}-\left(x+1\right)=18\sqrt{18}
Multiply both sides of the equation by 18.
126\sqrt{2}-x-1=18\sqrt{18}
To find the opposite of x+1, find the opposite of each term.
126\sqrt{2}-x-1=18\times 3\sqrt{2}
Factor 18=3^{2}\times 2. Rewrite the square root of the product \sqrt{3^{2}\times 2} as the product of square roots \sqrt{3^{2}}\sqrt{2}. Take the square root of 3^{2}.
126\sqrt{2}-x-1=54\sqrt{2}
Multiply 18 and 3 to get 54.
-x-1=54\sqrt{2}-126\sqrt{2}
Subtract 126\sqrt{2} from both sides.
-x-1=-72\sqrt{2}
Combine 54\sqrt{2} and -126\sqrt{2} to get -72\sqrt{2}.
-x=-72\sqrt{2}+1
Add 1 to both sides.
-x=1-72\sqrt{2}
The equation is in standard form.
\frac{-x}{-1}=\frac{1-72\sqrt{2}}{-1}
Divide both sides by -1.
x=\frac{1-72\sqrt{2}}{-1}
Dividing by -1 undoes the multiplication by -1.
x=72\sqrt{2}-1
Divide -72\sqrt{2}+1 by -1.