Solve 7quad2.5+4/5quad0quad-5.2quad-1/3quad+41

$$7 \quad 2.5 + \frac { 4 } { 5 } \quad 0 \quad - 5.2 \quad - \frac { 1 } { 3 } \quad + 41$$

Evaluate

$$\frac{1589}{30}\approx 52.966666667$$

Solution Steps

Multiply 7 and 2.5 to get 17.5.

$$17.5+\frac{4}{5}\times 0-5.2-\frac{1}{3}+41$$

Multiply \frac{4}{5} and 0 to get 0.

$$17.5+0-5.2-\frac{1}{3}+41$$

Add 17.5 and 0 to get 17.5.

$$17.5-5.2-\frac{1}{3}+41$$

Subtract 5.2 from 17.5 to get 12.3.

$$12.3-\frac{1}{3}+41$$

Convert decimal number 12.3 to fraction \frac{123}{10}.

$$\frac{123}{10}-\frac{1}{3}+41$$

Least common multiple of 10 and 3 is 30. Convert \frac{123}{10} and \frac{1}{3} to fractions with denominator 30.

$$\frac{369}{30}-\frac{10}{30}+41$$

Since \frac{369}{30} and \frac{10}{30} have the same denominator, subtract them by subtracting their numerators.

$$\frac{369-10}{30}+41$$

Subtract 10 from 369 to get 359.

$$\frac{359}{30}+41$$

Convert 41 to fraction \frac{1230}{30}.

$$\frac{359}{30}+\frac{1230}{30}$$

Since \frac{359}{30} and \frac{1230}{30} have the same denominator, add them by adding their numerators.

$$\frac{359+1230}{30}$$

Add 359 and 1230 to get 1589.

$$\frac{1589}{30}$$

Factor

$$\frac{7 \cdot 227}{2 \cdot 3 \cdot 5} = 52\frac{29}{30} = 52.96666666666667$$