Solve 7leq3y/5+11

$$7 \leq \frac { 3 y } { 5 } + 11$$

Solve for y

$$y\geq -\frac{20}{3}$$

Solution Steps

Multiply both sides of the equation by 5. Since 5 is positive, the inequality direction remains the same.

$$35\leq 3y+55$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$3y+55\geq 35$$

Subtract 55 from both sides.

$$3y\geq 35-55$$

Subtract 55 from 35 to get -20.

$$3y\geq -20$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$y\geq -\frac{20}{3}$$