Solve 77x+5/3=4

$$7 \frac { 7 x + 5 } { 3 } = 4$$

Solve for x

$$x=-\frac{23}{49}\approx -0.469387755$$

Steps for Solving Linear Equation

Divide both sides by 7.

$$\frac{7x+5}{3}=\frac{4}{7}$$

Multiply both sides by 3.

$$7x+5=\frac{4}{7}\times 3$$

Express \frac{4}{7}\times 3 as a single fraction.

$$7x+5=\frac{4\times 3}{7}$$

Multiply 4 and 3 to get 12.

$$7x+5=\frac{12}{7}$$

Subtract 5 from both sides.

$$7x=\frac{12}{7}-5$$

Convert 5 to fraction \frac{35}{7}.

$$7x=\frac{12}{7}-\frac{35}{7}$$

Since \frac{12}{7} and \frac{35}{7} have the same denominator, subtract them by subtracting their numerators.

$$7x=\frac{12-35}{7}$$

Subtract 35 from 12 to get -23.

$$7x=-\frac{23}{7}$$

Divide both sides by 7.

$$x=\frac{-\frac{23}{7}}{7}$$

Express \frac{-\frac{23}{7}}{7} as a single fraction.

$$x=\frac{-23}{7\times 7}$$

Multiply 7 and 7 to get 49.

$$x=\frac{-23}{49}$$

Fraction \frac{-23}{49} can be rewritten as -\frac{23}{49} by extracting the negative sign.

$$x=-\frac{23}{49}$$