Solve 74/19-(26/57+11/19)

$$7 \frac { 4 } { 19 } - ( 2 \frac { 6 } { 57 } + 1 \frac { 1 } { 19 } )$$

Evaluate

$$\frac{77}{19}\approx 4.052631579$$

Solution Steps

Multiply 7 and 19 to get 133.

$$\frac{133+4}{19}-\left(\frac{2\times 57+6}{57}+\frac{1\times 19+1}{19}\right)$$

Add 133 and 4 to get 137.

$$\frac{137}{19}-\left(\frac{2\times 57+6}{57}+\frac{1\times 19+1}{19}\right)$$

Multiply 2 and 57 to get 114.

$$\frac{137}{19}-\left(\frac{114+6}{57}+\frac{1\times 19+1}{19}\right)$$

Add 114 and 6 to get 120.

$$\frac{137}{19}-\left(\frac{120}{57}+\frac{1\times 19+1}{19}\right)$$

Reduce the fraction \frac{120}{57} to lowest terms by extracting and canceling out 3.

$$\frac{137}{19}-\left(\frac{40}{19}+\frac{1\times 19+1}{19}\right)$$

Multiply 1 and 19 to get 19.

$$\frac{137}{19}-\left(\frac{40}{19}+\frac{19+1}{19}\right)$$

Add 19 and 1 to get 20.

$$\frac{137}{19}-\left(\frac{40}{19}+\frac{20}{19}\right)$$

Since \frac{40}{19} and \frac{20}{19} have the same denominator, add them by adding their numerators.

$$\frac{137}{19}-\frac{40+20}{19}$$

Add 40 and 20 to get 60.

$$\frac{137}{19}-\frac{60}{19}$$

Since \frac{137}{19} and \frac{60}{19} have the same denominator, subtract them by subtracting their numerators.

$$\frac{137-60}{19}$$

Subtract 60 from 137 to get 77.

$$\frac{77}{19}$$

Factor

$$\frac{7 \cdot 11}{19} = 4\frac{1}{19} = 4.052631578947368$$