Solve 73/4-5/8+15/6

$$7 \frac { 3 } { 4 } - \frac { 5 } { 8 } + 1 \frac { 5 } { 6 }$$

Evaluate

$$\frac{215}{24}\approx 8.958333333$$

Solution Steps

Multiply 7 and 4 to get 28.

$$\frac{28+3}{4}-\frac{5}{8}+\frac{1\times 6+5}{6}$$

Add 28 and 3 to get 31.

$$\frac{31}{4}-\frac{5}{8}+\frac{1\times 6+5}{6}$$

Least common multiple of 4 and 8 is 8. Convert \frac{31}{4} and \frac{5}{8} to fractions with denominator 8.

$$\frac{62}{8}-\frac{5}{8}+\frac{1\times 6+5}{6}$$

Since \frac{62}{8} and \frac{5}{8} have the same denominator, subtract them by subtracting their numerators.

$$\frac{62-5}{8}+\frac{1\times 6+5}{6}$$

Subtract 5 from 62 to get 57.

$$\frac{57}{8}+\frac{1\times 6+5}{6}$$

Multiply 1 and 6 to get 6.

$$\frac{57}{8}+\frac{6+5}{6}$$

Add 6 and 5 to get 11.

$$\frac{57}{8}+\frac{11}{6}$$

Least common multiple of 8 and 6 is 24. Convert \frac{57}{8} and \frac{11}{6} to fractions with denominator 24.

$$\frac{171}{24}+\frac{44}{24}$$

Since \frac{171}{24} and \frac{44}{24} have the same denominator, add them by adding their numerators.

$$\frac{171+44}{24}$$

Add 171 and 44 to get 215.

$$\frac{215}{24}$$

Factor

$$\frac{5 \cdot 43}{2 ^ {3} \cdot 3} = 8\frac{23}{24} = 8.958333333333334$$