Solve 72/6+34/12

$$7 \frac { 2 } { 6 } + 3 \frac { 4 } { 12 }$$

Evaluate

$$\frac{32}{3}\approx 10.666666667$$

Solution Steps

Multiply 7 and 6 to get 42.

$$\frac{42+2}{6}+\frac{3\times 12+4}{12}$$

Add 42 and 2 to get 44.

$$\frac{44}{6}+\frac{3\times 12+4}{12}$$

Reduce the fraction \frac{44}{6} to lowest terms by extracting and canceling out 2.

$$\frac{22}{3}+\frac{3\times 12+4}{12}$$

Multiply 3 and 12 to get 36.

$$\frac{22}{3}+\frac{36+4}{12}$$

Add 36 and 4 to get 40.

$$\frac{22}{3}+\frac{40}{12}$$

Reduce the fraction \frac{40}{12} to lowest terms by extracting and canceling out 4.

$$\frac{22}{3}+\frac{10}{3}$$

Since \frac{22}{3} and \frac{10}{3} have the same denominator, add them by adding their numerators.

$$\frac{22+10}{3}$$

Add 22 and 10 to get 32.

$$\frac{32}{3}$$

Factor

$$\frac{2 ^ {5}}{3} = 10\frac{2}{3} = 10.666666666666666$$