Solve 71/8+35/24=

$$7 \frac { 1 } { 8 } + 3 \frac { 5 } { 24 } =$$

Evaluate

$$\frac{31}{3}\approx 10.333333333$$

Solution Steps

Multiply 7 and 8 to get 56.

$$\frac{56+1}{8}+\frac{3\times 24+5}{24}$$

Add 56 and 1 to get 57.

$$\frac{57}{8}+\frac{3\times 24+5}{24}$$

Multiply 3 and 24 to get 72.

$$\frac{57}{8}+\frac{72+5}{24}$$

Add 72 and 5 to get 77.

$$\frac{57}{8}+\frac{77}{24}$$

Least common multiple of 8 and 24 is 24. Convert \frac{57}{8} and \frac{77}{24} to fractions with denominator 24.

$$\frac{171}{24}+\frac{77}{24}$$

Since \frac{171}{24} and \frac{77}{24} have the same denominator, add them by adding their numerators.

$$\frac{171+77}{24}$$

Add 171 and 77 to get 248.

$$\frac{248}{24}$$

Reduce the fraction \frac{248}{24} to lowest terms by extracting and canceling out 8.

$$\frac{31}{3}$$

Factor

$$\frac{31}{3} = 10\frac{1}{3} = 10.333333333333334$$