Solve 71/6-31/4

$$7 \frac { 1 } { 6 } - 3 \frac { 1 } { 4 }$$

Evaluate

$$\frac{47}{12}\approx 3.916666667$$

Solution Steps

Multiply 7 and 6 to get 42.

$$\frac{42+1}{6}-\frac{3\times 4+1}{4}$$

Add 42 and 1 to get 43.

$$\frac{43}{6}-\frac{3\times 4+1}{4}$$

Multiply 3 and 4 to get 12.

$$\frac{43}{6}-\frac{12+1}{4}$$

Add 12 and 1 to get 13.

$$\frac{43}{6}-\frac{13}{4}$$

Least common multiple of 6 and 4 is 12. Convert \frac{43}{6} and \frac{13}{4} to fractions with denominator 12.

$$\frac{86}{12}-\frac{39}{12}$$

Since \frac{86}{12} and \frac{39}{12} have the same denominator, subtract them by subtracting their numerators.

$$\frac{86-39}{12}$$

Subtract 39 from 86 to get 47.

$$\frac{47}{12}$$

Factor

$$\frac{47}{2 ^ {2} \cdot 3} = 3\frac{11}{12} = 3.9166666666666665$$