Solve 71/6+101/7

$$7 \frac { 1 } { 6 } + 10 \frac { 1 } { 7 }$$

Evaluate

$$\frac{727}{42}\approx 17.30952381$$

Solution Steps

Multiply 7 and 6 to get 42.

$$\frac{42+1}{6}+\frac{10\times 7+1}{7}$$

Add 42 and 1 to get 43.

$$\frac{43}{6}+\frac{10\times 7+1}{7}$$

Multiply 10 and 7 to get 70.

$$\frac{43}{6}+\frac{70+1}{7}$$

Add 70 and 1 to get 71.

$$\frac{43}{6}+\frac{71}{7}$$

Least common multiple of 6 and 7 is 42. Convert \frac{43}{6} and \frac{71}{7} to fractions with denominator 42.

$$\frac{301}{42}+\frac{426}{42}$$

Since \frac{301}{42} and \frac{426}{42} have the same denominator, add them by adding their numerators.

$$\frac{301+426}{42}$$

Add 301 and 426 to get 727.

$$\frac{727}{42}$$

Factor

$$\frac{727}{2 \cdot 3 \cdot 7} = 17\frac{13}{42} = 17.30952380952381$$