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\frac{\left(7\times 3+1\right)\times 3}{3\left(1\times 3+1\right)}
Divide \frac{7\times 3+1}{3} by \frac{1\times 3+1}{3} by multiplying \frac{7\times 3+1}{3} by the reciprocal of \frac{1\times 3+1}{3}.
\frac{1+3\times 7}{1+3}
Cancel out 3 in both numerator and denominator.
\frac{1+21}{1+3}
Multiply 3 and 7 to get 21.
\frac{22}{1+3}
Add 1 and 21 to get 22.
\frac{22}{4}
Add 1 and 3 to get 4.
\frac{11}{2}
Reduce the fraction \frac{22}{4} to lowest terms by extracting and canceling out 2.