Solve 71/3+54/9-44/9

$$7 \frac { 1 } { 3 } + 5 \frac { 4 } { 9 } - 4 \frac { 4 } { 9 }$$

Evaluate

$$\frac{25}{3}\approx 8.333333333$$

Solution Steps

Multiply 7 and 3 to get 21.

$$\frac{21+1}{3}+\frac{5\times 9+4}{9}-\frac{4\times 9+4}{9}$$

Add 21 and 1 to get 22.

$$\frac{22}{3}+\frac{5\times 9+4}{9}-\frac{4\times 9+4}{9}$$

Multiply 5 and 9 to get 45.

$$\frac{22}{3}+\frac{45+4}{9}-\frac{4\times 9+4}{9}$$

Add 45 and 4 to get 49.

$$\frac{22}{3}+\frac{49}{9}-\frac{4\times 9+4}{9}$$

Least common multiple of 3 and 9 is 9. Convert \frac{22}{3} and \frac{49}{9} to fractions with denominator 9.

$$\frac{66}{9}+\frac{49}{9}-\frac{4\times 9+4}{9}$$

Since \frac{66}{9} and \frac{49}{9} have the same denominator, add them by adding their numerators.

$$\frac{66+49}{9}-\frac{4\times 9+4}{9}$$

Add 66 and 49 to get 115.

$$\frac{115}{9}-\frac{4\times 9+4}{9}$$

Multiply 4 and 9 to get 36.

$$\frac{115}{9}-\frac{36+4}{9}$$

Add 36 and 4 to get 40.

$$\frac{115}{9}-\frac{40}{9}$$

Since \frac{115}{9} and \frac{40}{9} have the same denominator, subtract them by subtracting their numerators.

$$\frac{115-40}{9}$$

Subtract 40 from 115 to get 75.

$$\frac{75}{9}$$

Reduce the fraction \frac{75}{9} to lowest terms by extracting and canceling out 3.

$$\frac{25}{3}$$

Factor

$$\frac{5 ^ {2}}{3} = 8\frac{1}{3} = 8.333333333333334$$