Solve 71/3+53/5

$$7 \frac { 1 } { 3 } + 5 \frac { 3 } { 5 }$$

Evaluate

$$\frac{194}{15}\approx 12.933333333$$

Solution Steps

Multiply 7 and 3 to get 21.

$$\frac{21+1}{3}+\frac{5\times 5+3}{5}$$

Add 21 and 1 to get 22.

$$\frac{22}{3}+\frac{5\times 5+3}{5}$$

Multiply 5 and 5 to get 25.

$$\frac{22}{3}+\frac{25+3}{5}$$

Add 25 and 3 to get 28.

$$\frac{22}{3}+\frac{28}{5}$$

Least common multiple of 3 and 5 is 15. Convert \frac{22}{3} and \frac{28}{5} to fractions with denominator 15.

$$\frac{110}{15}+\frac{84}{15}$$

Since \frac{110}{15} and \frac{84}{15} have the same denominator, add them by adding their numerators.

$$\frac{110+84}{15}$$

Add 110 and 84 to get 194.

$$\frac{194}{15}$$

Factor

$$\frac{2 \cdot 97}{3 \cdot 5} = 12\frac{14}{15} = 12.933333333333334$$