Solve 71/2-3/5+6=

$$7 \frac { 1 } { 2 } - \frac { 3 } { 5 } + 6 =$$

Evaluate

$$\frac{129}{10}=12.9$$

Solution Steps

Multiply 7 and 2 to get 14.

$$\frac{14+1}{2}-\frac{3}{5}+6$$

Add 14 and 1 to get 15.

$$\frac{15}{2}-\frac{3}{5}+6$$

Least common multiple of 2 and 5 is 10. Convert \frac{15}{2} and \frac{3}{5} to fractions with denominator 10.

$$\frac{75}{10}-\frac{6}{10}+6$$

Since \frac{75}{10} and \frac{6}{10} have the same denominator, subtract them by subtracting their numerators.

$$\frac{75-6}{10}+6$$

Subtract 6 from 75 to get 69.

$$\frac{69}{10}+6$$

Convert 6 to fraction \frac{60}{10}.

$$\frac{69}{10}+\frac{60}{10}$$

Since \frac{69}{10} and \frac{60}{10} have the same denominator, add them by adding their numerators.

$$\frac{69+60}{10}$$

Add 69 and 60 to get 129.

$$\frac{129}{10}$$

Factor

$$\frac{3 \cdot 43}{2 \cdot 5} = 12\frac{9}{10} = 12.9$$