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\frac{\left(7\times 2+1\right)\times 8}{2\left(2\times 8+5\right)}
Divide \frac{7\times 2+1}{2} by \frac{2\times 8+5}{8} by multiplying \frac{7\times 2+1}{2} by the reciprocal of \frac{2\times 8+5}{8}.
\frac{4\left(1+2\times 7\right)}{5+2\times 8}
Cancel out 2 in both numerator and denominator.
\frac{4\left(1+14\right)}{5+2\times 8}
Multiply 2 and 7 to get 14.
\frac{4\times 15}{5+2\times 8}
Add 1 and 14 to get 15.
\frac{60}{5+2\times 8}
Multiply 4 and 15 to get 60.
\frac{60}{5+16}
Multiply 2 and 8 to get 16.
\frac{60}{21}
Add 5 and 16 to get 21.
\frac{20}{7}
Reduce the fraction \frac{60}{21} to lowest terms by extracting and canceling out 3.