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\frac{\left(7\times 2+1\right)\times 5}{2\left(1\times 5+1\right)}
Divide \frac{7\times 2+1}{2} by \frac{1\times 5+1}{5} by multiplying \frac{7\times 2+1}{2} by the reciprocal of \frac{1\times 5+1}{5}.
\frac{\left(14+1\right)\times 5}{2\left(1\times 5+1\right)}
Multiply 7 and 2 to get 14.
\frac{15\times 5}{2\left(1\times 5+1\right)}
Add 14 and 1 to get 15.
\frac{75}{2\left(1\times 5+1\right)}
Multiply 15 and 5 to get 75.
\frac{75}{2\left(5+1\right)}
Multiply 1 and 5 to get 5.
\frac{75}{2\times 6}
Add 5 and 1 to get 6.
\frac{75}{12}
Multiply 2 and 6 to get 12.
\frac{25}{4}
Reduce the fraction \frac{75}{12} to lowest terms by extracting and canceling out 3.