Solve 71/2div1*2-{12*(1/3-03)-3/20}

$$7 \frac { 1 } { 2 } \div 1 \cdot 2 - \{ 12 \times ( \frac { 1 } { 3 } - 03 ) - \frac { 3 } { 20 } \}$$

Evaluate

$$\frac{223}{20}=11.15$$

Solution Steps

Multiply 7 and 2 to get 14.

$$\frac{\frac{14+1}{2}}{1}\times 2-\left(12\left(\frac{1}{3}-0\times 3\right)-\frac{3}{20}\right)$$

Add 14 and 1 to get 15.

$$\frac{\frac{15}{2}}{1}\times 2-\left(12\left(\frac{1}{3}-0\times 3\right)-\frac{3}{20}\right)$$

Anything divided by one gives itself.

$$\frac{15}{2}\times 2-\left(12\left(\frac{1}{3}-0\times 3\right)-\frac{3}{20}\right)$$

Cancel out 2 and 2.

$$15-\left(12\left(\frac{1}{3}-0\times 3\right)-\frac{3}{20}\right)$$

Multiply 0 and 3 to get 0.

$$15-\left(12\left(\frac{1}{3}-0\right)-\frac{3}{20}\right)$$

Subtract 0 from \frac{1}{3} to get \frac{1}{3}.

$$15-\left(12\times \frac{1}{3}-\frac{3}{20}\right)$$

Multiply 12 and \frac{1}{3} to get \frac{12}{3}.

$$15-\left(\frac{12}{3}-\frac{3}{20}\right)$$

Divide 12 by 3 to get 4.

$$15-\left(4-\frac{3}{20}\right)$$

Convert 4 to fraction \frac{80}{20}.

$$15-\left(\frac{80}{20}-\frac{3}{20}\right)$$

Since \frac{80}{20} and \frac{3}{20} have the same denominator, subtract them by subtracting their numerators.

$$15-\frac{80-3}{20}$$

Subtract 3 from 80 to get 77.

$$15-\frac{77}{20}$$

Convert 15 to fraction \frac{300}{20}.

$$\frac{300}{20}-\frac{77}{20}$$

Since \frac{300}{20} and \frac{77}{20} have the same denominator, subtract them by subtracting their numerators.

$$\frac{300-77}{20}$$

Subtract 77 from 300 to get 223.

$$\frac{223}{20}$$

Factor

$$\frac{223}{2 ^ {2} \cdot 5} = 11\frac{3}{20} = 11.15$$