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\frac{\left(7\times 2+1\right)\times 2}{2\left(4\times 2+1\right)}=\frac{x}{\frac{3}{25}}
Divide \frac{7\times 2+1}{2} by \frac{4\times 2+1}{2} by multiplying \frac{7\times 2+1}{2} by the reciprocal of \frac{4\times 2+1}{2}.
\frac{1+2\times 7}{1+2\times 4}=\frac{x}{\frac{3}{25}}
Cancel out 2 in both numerator and denominator.
\frac{1+14}{1+2\times 4}=\frac{x}{\frac{3}{25}}
Multiply 2 and 7 to get 14.
\frac{15}{1+2\times 4}=\frac{x}{\frac{3}{25}}
Add 1 and 14 to get 15.
\frac{15}{1+8}=\frac{x}{\frac{3}{25}}
Multiply 2 and 4 to get 8.
\frac{15}{9}=\frac{x}{\frac{3}{25}}
Add 1 and 8 to get 9.
\frac{5}{3}=\frac{x}{\frac{3}{25}}
Reduce the fraction \frac{15}{9} to lowest terms by extracting and canceling out 3.
\frac{x}{\frac{3}{25}}=\frac{5}{3}
Swap sides so that all variable terms are on the left hand side.
x=\frac{5}{3}\times \frac{3}{25}
Multiply both sides by \frac{3}{25}.
x=\frac{5\times 3}{3\times 25}
Multiply \frac{5}{3} times \frac{3}{25} by multiplying numerator times numerator and denominator times denominator.
x=\frac{5}{25}
Cancel out 3 in both numerator and denominator.
x=\frac{1}{5}
Reduce the fraction \frac{5}{25} to lowest terms by extracting and canceling out 5.