Solve 7*8^3+6*8^2+5*8^1+2*8^0

$$7 \cdot 8 ^ { 3 } + 6 \cdot 8 ^ { 2 } + 5 \cdot 8 ^ { 1 } + 2 \cdot 8 ^ { 0 }$$

Evaluate

$$4010$$

Solution Steps

Calculate 8 to the power of 3 and get 512.

$$7\times 512+6\times 8^{2}+5\times 8^{1}+2\times 8^{0}$$

Multiply 7 and 512 to get 3584.

$$3584+6\times 8^{2}+5\times 8^{1}+2\times 8^{0}$$

Calculate 8 to the power of 2 and get 64.

$$3584+6\times 64+5\times 8^{1}+2\times 8^{0}$$

Multiply 6 and 64 to get 384.

$$3584+384+5\times 8^{1}+2\times 8^{0}$$

Add 3584 and 384 to get 3968.

$$3968+5\times 8^{1}+2\times 8^{0}$$

Calculate 8 to the power of 1 and get 8.

$$3968+5\times 8+2\times 8^{0}$$

Multiply 5 and 8 to get 40.

$$3968+40+2\times 8^{0}$$

Add 3968 and 40 to get 4008.

$$4008+2\times 8^{0}$$

Calculate 8 to the power of 0 and get 1.

$$4008+2\times 1$$

Multiply 2 and 1 to get 2.

$$4008+2$$

Add 4008 and 2 to get 4010.

$$4010$$

Factor

$$2\times 5\times 401$$