Solve 7*3/-6-21-6

$$7 \cdot \frac { 3 } { - 6 } - 21 - 6$$

Evaluate

$$-\frac{61}{2}=-30.5$$

Solution Steps

Reduce the fraction \frac{3}{-6} to lowest terms by extracting and canceling out 3.

$$7\left(-\frac{1}{2}\right)-21-6$$

Express 7\left(-\frac{1}{2}\right) as a single fraction.

$$\frac{7\left(-1\right)}{2}-21-6$$

Multiply 7 and -1 to get -7.

$$\frac{-7}{2}-21-6$$

Fraction \frac{-7}{2} can be rewritten as -\frac{7}{2} by extracting the negative sign.

$$-\frac{7}{2}-21-6$$

Convert 21 to fraction \frac{42}{2}.

$$-\frac{7}{2}-\frac{42}{2}-6$$

Since -\frac{7}{2} and \frac{42}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-7-42}{2}-6$$

Subtract 42 from -7 to get -49.

$$-\frac{49}{2}-6$$

Convert 6 to fraction \frac{12}{2}.

$$-\frac{49}{2}-\frac{12}{2}$$

Since -\frac{49}{2} and \frac{12}{2} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-49-12}{2}$$

Subtract 12 from -49 to get -61.

$$-\frac{61}{2}$$

Factor

$$-\frac{61}{2} = -30\frac{1}{2} = -30.5$$