Solve for x
x=-\log_{7}\left(10\right)+2\approx 0.816705338
Solve for x (complex solution)
x=\frac{i\times 2\pi n_{1}}{3\ln(7)}-\log_{7}\left(10\right)+2
n_{1}\in \mathrm{Z}
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7^{3x}=117.649
Use the rules of exponents and logarithms to solve the equation.
\log(7^{3x})=\log(117.649)
Take the logarithm of both sides of the equation.
3x\log(7)=\log(117.649)
The logarithm of a number raised to a power is the power times the logarithm of the number.
3x=\frac{\log(117.649)}{\log(7)}
Divide both sides by \log(7).
3x=\log_{7}\left(117.649\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
x=\frac{-3\log_{7}\left(10\right)+6}{3}
Divide both sides by 3.
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