Solve 7^2-4*2*(-4)=81>0

$$7 ^ { 2 } - 4 \times 2 \times ( - 4 ) = 81 > 0$$

Verify

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$49-4\times 2\left(-4\right)=81\text{ and }81>0$$

Multiply 4 and 2 to get 8.

$$49-8\left(-4\right)=81\text{ and }81>0$$

Multiply 8 and -4 to get -32.

$$49-\left(-32\right)=81\text{ and }81>0$$

The opposite of -32 is 32.

$$49+32=81\text{ and }81>0$$

Add 49 and 32 to get 81.

$$81=81\text{ and }81>0$$

Compare 81 and 81.

$$\text{true}\text{ and }81>0$$

Compare 81 and 0.

$$\text{true}\text{ and }\text{true}$$

The conjunction of \text{true} and \text{true} is \text{true}.

$$\text{true}$$