Solve 7^2(43-15)+sqrt{121}(7-84)((-3)^3+20)

$$7 ^ { 2 } ( 43 - 15 ) + \sqrt { 121 } ( 7 - 84 ) ( ( - 3 ) ^ { 3 } + 20 )$$

Evaluate

$$7301$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$49\left(43-15\right)+\sqrt{121}\left(7-84\right)\left(\left(-3\right)^{3}+20\right)$$

Subtract 15 from 43 to get 28.

$$49\times 28+\sqrt{121}\left(7-84\right)\left(\left(-3\right)^{3}+20\right)$$

Multiply 49 and 28 to get 1372.

$$1372+\sqrt{121}\left(7-84\right)\left(\left(-3\right)^{3}+20\right)$$

Calculate the square root of 121 and get 11.

$$1372+11\left(7-84\right)\left(\left(-3\right)^{3}+20\right)$$

Subtract 84 from 7 to get -77.

$$1372+11\left(-77\right)\left(\left(-3\right)^{3}+20\right)$$

Multiply 11 and -77 to get -847.

$$1372-847\left(\left(-3\right)^{3}+20\right)$$

Calculate -3 to the power of 3 and get -27.

$$1372-847\left(-27+20\right)$$

Add -27 and 20 to get -7.

$$1372-847\left(-7\right)$$

Multiply -847 and -7 to get 5929.

$$1372+5929$$

Add 1372 and 5929 to get 7301.

$$7301$$

Factor

$$7^{2}\times 149$$