Solve 7^2[(2-3)+6]-64^13{6+[3+2(4+2)^2-1](-1)}

$$7 ^ { 2 } [ ( 2 - 3 ) + 6 ] - 64 ^ { 13 } \{ 6 + [ 3 + 2 ( 4 + 2 ) ^ { 2 } - 1 ] ( - 1 ) \}$$

Evaluate

$$20551738933448695970005237$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$49\left(2-3+6\right)-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Subtract 3 from 2 to get -1.

$$49\left(-1+6\right)-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Add -1 and 6 to get 5.

$$49\times 5-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Multiply 49 and 5 to get 245.

$$245-64^{13}\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Calculate 64 to the power of 13 and get 302231454903657293676544.

$$245-302231454903657293676544\left(6+\left(3+2\left(4+2\right)^{2}-1\right)\left(-1\right)\right)$$

Add 4 and 2 to get 6.

$$245-302231454903657293676544\left(6+\left(3+2\times 6^{2}-1\right)\left(-1\right)\right)$$

Calculate 6 to the power of 2 and get 36.

$$245-302231454903657293676544\left(6+\left(3+2\times 36-1\right)\left(-1\right)\right)$$

Multiply 2 and 36 to get 72.

$$245-302231454903657293676544\left(6+\left(3+72-1\right)\left(-1\right)\right)$$

Add 3 and 72 to get 75.

$$245-302231454903657293676544\left(6+\left(75-1\right)\left(-1\right)\right)$$

Subtract 1 from 75 to get 74.

$$245-302231454903657293676544\left(6+74\left(-1\right)\right)$$

Multiply 74 and -1 to get -74.

$$245-302231454903657293676544\left(6-74\right)$$

Subtract 74 from 6 to get -68.

$$245-302231454903657293676544\left(-68\right)$$

Multiply 302231454903657293676544 and -68 to get -20551738933448695970004992.

$$245-\left(-20551738933448695970004992\right)$$

The opposite of -20551738933448695970004992 is 20551738933448695970004992.

$$245+20551738933448695970004992$$

Add 245 and 20551738933448695970004992 to get 20551738933448695970005237.

$$20551738933448695970005237$$

Factor

$$127\times 16657\times 9715117728967224283$$