Solve 7^2=5^2+3^2-2*5*3*x

$$7 ^ { 2 } = 5 ^ { 2 } + 3 ^ { 2 } - 2 \times 5 \times 3 \times x$$

Solve for x

$$x=-\frac{1}{2}=-0.5$$

Steps for Solving Linear Equation

Calculate 7 to the power of 2 and get 49.

$$49=5^{2}+3^{2}-2\times 5\times 3x$$

Calculate 5 to the power of 2 and get 25.

$$49=25+3^{2}-2\times 5\times 3x$$

Calculate 3 to the power of 2 and get 9.

$$49=25+9-2\times 5\times 3x$$

Add 25 and 9 to get 34.

$$49=34-2\times 5\times 3x$$

Multiply 2 and 5 to get 10.

$$49=34-10\times 3x$$

Multiply 10 and 3 to get 30.

$$49=34-30x$$

Swap sides so that all variable terms are on the left hand side.

$$34-30x=49$$

Subtract 34 from both sides.

$$-30x=49-34$$

Subtract 34 from 49 to get 15.

$$-30x=15$$

Divide both sides by -30.

$$x=\frac{15}{-30}$$

Reduce the fraction \frac{15}{-30} to lowest terms by extracting and canceling out 15.

$$x=-\frac{1}{2}$$