Solve 7^{2}+3x=(24^4:12^4*2^-2:2*2^0)x

$$7 ^ { 2 } + 3 x = ( 24 ^ { 4 } : 12 ^ { 4 } \cdot 2 ^ { - 2 } : 2 \cdot 2 ^ { 0 } ) x$$

Solve for x

$$x=-49$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$2\times 7^{2}+6x=\frac{24^{4}}{12^{4}}\times 2^{-2}\times 2^{0}x$$

Calculate 7 to the power of 2 and get 49.

$$2\times 49+6x=\frac{24^{4}}{12^{4}}\times 2^{-2}\times 2^{0}x$$

Multiply 2 and 49 to get 98.

$$98+6x=\frac{24^{4}}{12^{4}}\times 2^{-2}\times 2^{0}x$$

To multiply powers of the same base, add their exponents. Add -2 and 0 to get -2.

$$98+6x=\frac{24^{4}}{12^{4}}\times 2^{-2}x$$

Calculate 24 to the power of 4 and get 331776.

$$98+6x=\frac{331776}{12^{4}}\times 2^{-2}x$$

Calculate 12 to the power of 4 and get 20736.

$$98+6x=\frac{331776}{20736}\times 2^{-2}x$$

Divide 331776 by 20736 to get 16.

$$98+6x=16\times 2^{-2}x$$

Calculate 2 to the power of -2 and get \frac{1}{4}.

$$98+6x=16\times \frac{1}{4}x$$

Multiply 16 and \frac{1}{4} to get 4.

$$98+6x=4x$$

Subtract 4x from both sides.

$$98+6x-4x=0$$

Combine 6x and -4x to get 2x.

$$98+2x=0$$

Subtract 98 from both sides. Anything subtracted from zero gives its negation.

$$2x=-98$$

Divide both sides by 2.

$$x=\frac{-98}{2}$$

Divide -98 by 2 to get -49.

$$x=-49$$