Solve 7^13:7^11text{ede}2^-42^5?

$$7 ^ { 13 } : 7 ^ { 11 } \text { e de } 2 ^ { - 4 } 2 ^ { 5 } ?$$

Evaluate

$$98e^{2}d$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 11 from 13 to get 2.

$$7^{2}ede\times 2^{-4}\times 2^{5}$$

Multiply e and e to get e^{2}.

$$7^{2}e^{2}d\times 2^{-4}\times 2^{5}$$

To multiply powers of the same base, add their exponents. Add -4 and 5 to get 1.

$$7^{2}e^{2}d\times 2^{1}$$

Calculate 7 to the power of 2 and get 49.

$$49e^{2}d\times 2^{1}$$

Calculate 2 to the power of 1 and get 2.

$$49e^{2}d\times 2$$

Multiply 49 and 2 to get 98.

$$98e^{2}d$$

Differentiate w.r.t. d

$$98e^{2}$$