Solve 7=4+c^2-2C

$$7 = 4 + c ^ { 2 } - 2 C$$

Solve for C

$$C=\frac{c^{2}-3}{2}$$

Steps for Solving Linear Equation

Swap sides so that all variable terms are on the left hand side.

$$4+c^{2}-2C=7$$

Subtract 4 from both sides.

$$c^{2}-2C=7-4$$

Subtract 4 from 7 to get 3.

$$c^{2}-2C=3$$

Subtract c^{2} from both sides.

$$-2C=3-c^{2}$$

Divide both sides by -2.

$$\frac{-2C}{-2}=\frac{3-c^{2}}{-2}$$

Dividing by -2 undoes the multiplication by -2.

$$C=\frac{3-c^{2}}{-2}$$

Divide 3-c^{2} by -2.

$$C=\frac{c^{2}-3}{2}$$

Solve for c (complex solution)

$$c=-\sqrt{2C+3}$$

$$c=\sqrt{2C+3}$$

Solve for c

$$c=\sqrt{2C+3}$$

$$c=-\sqrt{2C+3}\text{, }C\geq -\frac{3}{2}$$