Solve for t
t=\frac{\log_{2}\left(\frac{7}{3}\right)}{4}\approx 0.305598105
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\frac{7}{3}=16^{t}
Divide both sides by 3.
16^{t}=\frac{7}{3}
Swap sides so that all variable terms are on the left hand side.
\log(16^{t})=\log(\frac{7}{3})
Take the logarithm of both sides of the equation.
t\log(16)=\log(\frac{7}{3})
The logarithm of a number raised to a power is the power times the logarithm of the number.
t=\frac{\log(\frac{7}{3})}{\log(16)}
Divide both sides by \log(16).
t=\log_{16}\left(\frac{7}{3}\right)
By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).
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