Solve 7+7*2+(-3)/2!*4+-5/3!2^3

$$7 + 7 \times 2 + \frac { ( - 3 ) } { 2 ! } \cdot 4 + \frac { - 5 } { 3 ! } 2 ^ { 3 }$$

Evaluate

$$\frac{25}{3}\approx 8.333333333$$

Solution Steps

Multiply 7 and 2 to get 14.

$$7+14+\frac{-3}{2!}\times 4+\frac{-5}{3!}\times 2^{3}$$

Add 7 and 14 to get 21.

$$21+\frac{-3}{2!}\times 4+\frac{-5}{3!}\times 2^{3}$$

The factorial of 2 is 2.

$$21+\frac{-3}{2}\times 4+\frac{-5}{3!}\times 2^{3}$$

Fraction \frac{-3}{2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$21-\frac{3}{2}\times 4+\frac{-5}{3!}\times 2^{3}$$

Express -\frac{3}{2}\times 4 as a single fraction.

$$21+\frac{-3\times 4}{2}+\frac{-5}{3!}\times 2^{3}$$

Multiply -3 and 4 to get -12.

$$21+\frac{-12}{2}+\frac{-5}{3!}\times 2^{3}$$

Divide -12 by 2 to get -6.

$$21-6+\frac{-5}{3!}\times 2^{3}$$

Subtract 6 from 21 to get 15.

$$15+\frac{-5}{3!}\times 2^{3}$$

The factorial of 3 is 6.

$$15+\frac{-5}{6}\times 2^{3}$$

Fraction \frac{-5}{6} can be rewritten as -\frac{5}{6} by extracting the negative sign.

$$15-\frac{5}{6}\times 2^{3}$$

Calculate 2 to the power of 3 and get 8.

$$15-\frac{5}{6}\times 8$$

Express -\frac{5}{6}\times 8 as a single fraction.

$$15+\frac{-5\times 8}{6}$$

Multiply -5 and 8 to get -40.

$$15+\frac{-40}{6}$$

Reduce the fraction \frac{-40}{6} to lowest terms by extracting and canceling out 2.

$$15-\frac{20}{3}$$

Convert 15 to fraction \frac{45}{3}.

$$\frac{45}{3}-\frac{20}{3}$$

Since \frac{45}{3} and \frac{20}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{45-20}{3}$$

Subtract 20 from 45 to get 25.

$$\frac{25}{3}$$

Factor

$$\frac{5 ^ {2}}{3} = 8\frac{1}{3} = 8.333333333333334$$