Solve for y
y=6
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\left(y-3\right)\times 7+3=4y
Variable y cannot be equal to 3 since division by zero is not defined. Multiply both sides of the equation by y-3.
7y-21+3=4y
Use the distributive property to multiply y-3 by 7.
7y-18=4y
Add -21 and 3 to get -18.
7y-18-4y=0
Subtract 4y from both sides.
3y-18=0
Combine 7y and -4y to get 3y.
3y=18
Add 18 to both sides. Anything plus zero gives itself.
y=\frac{18}{3}
Divide both sides by 3.
y=6
Divide 18 by 3 to get 6.
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