Solve 7+28/17(7*2+4)-32^3=

$$7 + \frac { 28 } { 17 } ( 7 \times 2 + 4 ) - 32 ^ { 3 } =$$

Evaluate

$$-\frac{556433}{17}\approx -32731.352941176$$

Solution Steps

Multiply 7 and 2 to get 14.

$$7+\frac{28}{17}\left(14+4\right)-32^{3}$$

Add 14 and 4 to get 18.

$$7+\frac{28}{17}\times 18-32^{3}$$

Express \frac{28}{17}\times 18 as a single fraction.

$$7+\frac{28\times 18}{17}-32^{3}$$

Multiply 28 and 18 to get 504.

$$7+\frac{504}{17}-32^{3}$$

Convert 7 to fraction \frac{119}{17}.

$$\frac{119}{17}+\frac{504}{17}-32^{3}$$

Since \frac{119}{17} and \frac{504}{17} have the same denominator, add them by adding their numerators.

$$\frac{119+504}{17}-32^{3}$$

Add 119 and 504 to get 623.

$$\frac{623}{17}-32^{3}$$

Calculate 32 to the power of 3 and get 32768.

$$\frac{623}{17}-32768$$

Convert 32768 to fraction \frac{557056}{17}.

$$\frac{623}{17}-\frac{557056}{17}$$

Since \frac{623}{17} and \frac{557056}{17} have the same denominator, subtract them by subtracting their numerators.

$$\frac{623-557056}{17}$$

Subtract 557056 from 623 to get -556433.

$$-\frac{556433}{17}$$

Factor

$$-\frac{556433}{17} = -32731\frac{6}{17} = -32731.352941176472$$