Solve 7+0.3x-0.2/0.2=1.5-5x/0.5

$$7 + \frac { 0.3 x - 0.2 } { 0.2 } = \frac { 1.5 - 5 x } { 0.5 }$$

Solve for x

$$x=-\frac{6}{23}\approx -0.260869565$$

Steps for Solving Linear Equation

Divide each term of 0.3x-0.2 by 0.2 to get \frac{0.3x}{0.2}+\frac{-0.2}{0.2}.

$$7+\frac{0.3x}{0.2}+\frac{-0.2}{0.2}=\frac{1.5-5x}{0.5}$$

Divide 0.3x by 0.2 to get 1.5x.

$$7+1.5x+\frac{-0.2}{0.2}=\frac{1.5-5x}{0.5}$$

Divide -0.2 by 0.2 to get -1.

$$7+1.5x-1=\frac{1.5-5x}{0.5}$$

Subtract 1 from 7 to get 6.

$$6+1.5x=\frac{1.5-5x}{0.5}$$

Divide each term of 1.5-5x by 0.5 to get \frac{1.5}{0.5}+\frac{-5x}{0.5}.

$$6+1.5x=\frac{1.5}{0.5}+\frac{-5x}{0.5}$$

Expand \frac{1.5}{0.5} by multiplying both numerator and the denominator by 10.

$$6+1.5x=\frac{15}{5}+\frac{-5x}{0.5}$$

Divide 15 by 5 to get 3.

$$6+1.5x=3+\frac{-5x}{0.5}$$

Divide -5x by 0.5 to get -10x.

$$6+1.5x=3-10x$$

Add 10x to both sides.

$$6+1.5x+10x=3$$

Combine 1.5x and 10x to get 11.5x.

$$6+11.5x=3$$

Subtract 6 from both sides.

$$11.5x=3-6$$

Subtract 6 from 3 to get -3.

$$11.5x=-3$$

Divide both sides by 11.5.

$$x=\frac{-3}{11.5}$$

Expand \frac{-3}{11.5} by multiplying both numerator and the denominator by 10.

$$x=\frac{-30}{115}$$

Reduce the fraction \frac{-30}{115} to lowest terms by extracting and canceling out 5.

$$x=-\frac{6}{23}$$