Solve 74/12+62/6

$$7 \frac { 4 } { 12 } + 6 \frac { 2 } { 6 }$$

Evaluate

$$\frac{41}{3}\approx 13.666666667$$

Solution Steps

Multiply 7 and 12 to get 84.

$$\frac{84+4}{12}+\frac{6\times 6+2}{6}$$

Add 84 and 4 to get 88.

$$\frac{88}{12}+\frac{6\times 6+2}{6}$$

Reduce the fraction \frac{88}{12} to lowest terms by extracting and canceling out 4.

$$\frac{22}{3}+\frac{6\times 6+2}{6}$$

Multiply 6 and 6 to get 36.

$$\frac{22}{3}+\frac{36+2}{6}$$

Add 36 and 2 to get 38.

$$\frac{22}{3}+\frac{38}{6}$$

Reduce the fraction \frac{38}{6} to lowest terms by extracting and canceling out 2.

$$\frac{22}{3}+\frac{19}{3}$$

Since \frac{22}{3} and \frac{19}{3} have the same denominator, add them by adding their numerators.

$$\frac{22+19}{3}$$

Add 22 and 19 to get 41.

$$\frac{41}{3}$$

Factor

$$\frac{41}{3} = 13\frac{2}{3} = 13.666666666666666$$