Solve for x
x=3\left(2y+z\right)
Solve for y
y=\frac{x-3z}{6}
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3z-x=-6y
Subtract 6y from both sides. Anything subtracted from zero gives its negation.
-x=-6y-3z
Subtract 3z from both sides.
\frac{-x}{-1}=\frac{-6y-3z}{-1}
Divide both sides by -1.
x=\frac{-6y-3z}{-1}
Dividing by -1 undoes the multiplication by -1.
x=6y+3z
Divide -6y-3z by -1.
6y-x=-3z
Subtract 3z from both sides. Anything subtracted from zero gives its negation.
6y=-3z+x
Add x to both sides.
6y=x-3z
The equation is in standard form.
\frac{6y}{6}=\frac{x-3z}{6}
Divide both sides by 6.
y=\frac{x-3z}{6}
Dividing by 6 undoes the multiplication by 6.
y=\frac{x}{6}-\frac{z}{2}
Divide -3z+x by 6.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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