Solve for x
x=\frac{9y+2240}{2\left(3y+2\right)}
y\neq -\frac{2}{3}
Solve for y
y=-\frac{4\left(x-560\right)}{3\left(2x-3\right)}
x\neq \frac{3}{2}
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6xy+4x-7=2233+9y
Add 9y to both sides.
6xy+4x=2233+9y+7
Add 7 to both sides.
6xy+4x=2240+9y
Add 2233 and 7 to get 2240.
\left(6y+4\right)x=2240+9y
Combine all terms containing x.
\left(6y+4\right)x=9y+2240
The equation is in standard form.
\frac{\left(6y+4\right)x}{6y+4}=\frac{9y+2240}{6y+4}
Divide both sides by 6y+4.
x=\frac{9y+2240}{6y+4}
Dividing by 6y+4 undoes the multiplication by 6y+4.
x=\frac{9y+2240}{2\left(3y+2\right)}
Divide 2240+9y by 6y+4.
6xy-9y-7=2233-4x
Subtract 4x from both sides.
6xy-9y=2233-4x+7
Add 7 to both sides.
6xy-9y=2240-4x
Add 2233 and 7 to get 2240.
\left(6x-9\right)y=2240-4x
Combine all terms containing y.
\frac{\left(6x-9\right)y}{6x-9}=\frac{2240-4x}{6x-9}
Divide both sides by 6x-9.
y=\frac{2240-4x}{6x-9}
Dividing by 6x-9 undoes the multiplication by 6x-9.
y=\frac{4\left(560-x\right)}{3\left(2x-3\right)}
Divide 2240-4x by 6x-9.
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