Solve 6x-4y=(4^2+1^2-13)div2

$$6x-4y=( { 4 }^{ 2 } + { 1 }^{ 2 } -13) \div 2$$

Solve for x

$$x=\frac{2y+1}{3}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$12x-8y=4^{2}+1^{2}-13$$

Calculate 4 to the power of 2 and get 16.

$$12x-8y=16+1^{2}-13$$

Calculate 1 to the power of 2 and get 1.

$$12x-8y=16+1-13$$

Add 16 and 1 to get 17.

$$12x-8y=17-13$$

Subtract 13 from 17 to get 4.

$$12x-8y=4$$

Add 8y to both sides.

$$12x=4+8y$$

The equation is in standard form.

$$12x=8y+4$$

Divide both sides by 12.

$$\frac{12x}{12}=\frac{8y+4}{12}$$

Dividing by 12 undoes the multiplication by 12.

$$x=\frac{8y+4}{12}$$

Divide 4+8y by 12.

$$x=\frac{2y+1}{3}$$

Solve for y

$$y=\frac{3x-1}{2}$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$12x-8y=4^{2}+1^{2}-13$$

Calculate 4 to the power of 2 and get 16.

$$12x-8y=16+1^{2}-13$$

Calculate 1 to the power of 2 and get 1.

$$12x-8y=16+1-13$$

Add 16 and 1 to get 17.

$$12x-8y=17-13$$

Subtract 13 from 17 to get 4.

$$12x-8y=4$$

Subtract 12x from both sides.

$$-8y=4-12x$$

Divide both sides by -8.

$$\frac{-8y}{-8}=\frac{4-12x}{-8}$$

Dividing by -8 undoes the multiplication by -8.

$$y=\frac{4-12x}{-8}$$

Divide 4-12x by -8.

$$y=\frac{3x-1}{2}$$